4n^2+2n+10=n^2

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Solution for 4n^2+2n+10=n^2 equation: 



4n^2+2n+10=n^2

We move all terms to the left:

4n^2+2n+10-(n^2)=0

determiningTheFunctionDomain
4n^2-n^2+2n+10=0

We add all the numbers together, and all the variables

3n^2+2n+10=0

a = 3; b = 2; c = +10;
Δ = b2-4ac
Δ = 22-4·3·10
Δ = -116
Delta is less than zero, so there is no solution for the equation

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